rationalise the determinors 1/root 5 +root 2
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1
given,
1/(√5+√2)
multiplying by √5 -√2
= (√5-√2)/3
1/(√5+√2)
multiplying by √5 -√2
= (√5-√2)/3
Answered by
1
1/√4+√2×1/√4-√2
1/√4^2-√2^2
1/4-2=1/2. (:a^2-b^2=(a+b)(a-b))
1/√4^2-√2^2
1/4-2=1/2. (:a^2-b^2=(a+b)(a-b))
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