Math, asked by adarshzimandm51111, 11 months ago

5x_3y=13and 2 x+3y=1

Answers

Answered by farazhussain63
4

Step-by-step explanation:

2x-3y=13;5x+3y=1

2x-3y=13;5x+3y=1 Solution :

2x-3y=13;5x+3y=1 Solution : {x,y} = {2,-3}

System of Linear Equations entered :

of Linear Equations entered : [1] 2x - 3y = 13

of Linear Equations entered : [1] 2x - 3y = 13 [2] 5x + 3y = 1

of Linear Equations entered : [1] 2x - 3y = 13 [2] 5x + 3y = 1Graphic Representation of the Equations :

of Linear Equations entered : [1] 2x - 3y = 13 [2] 5x + 3y = 1Graphic Representation of the Equations : -3y + 2x = 13 3y + 5x = 1

of Linear Equations entered : [1] 2x - 3y = 13 [2] 5x + 3y = 1Graphic Representation of the Equations : -3y + 2x = 13 3y + 5x = 1 Solve by Substitution :

of Linear Equations entered : [1] 2x - 3y = 13 [2] 5x + 3y = 1Graphic Representation of the Equations : -3y + 2x = 13 3y + 5x = 1 Solve by Substitution :// Solve equation [2] for the variable y

of Linear Equations entered : [1] 2x - 3y = 13 [2] 5x + 3y = 1Graphic Representation of the Equations : -3y + 2x = 13 3y + 5x = 1 Solve by Substitution :// Solve equation [2] for the variable y

[2] 3y = -5x + 1

2] 3y = -5x + 1 [2] y = -5x/3 + 1/3

2] 3y = -5x + 1 [2] y = -5x/3 + 1/3// Plug this in for variable y in equation [1]

2] 3y = -5x + 1 [2] y = -5x/3 + 1/3// Plug this in for variable y in equation [1] [1] 2x - 3•(-5x/3+1/3) = 13

2] 3y = -5x + 1 [2] y = -5x/3 + 1/3// Plug this in for variable y in equation [1] [1] 2x - 3•(-5x/3+1/3) = 13 [1] 7x = 14

2] 3y = -5x + 1 [2] y = -5x/3 + 1/3// Plug this in for variable y in equation [1] [1] 2x - 3•(-5x/3+1/3) = 13 [1] 7x = 14// Solve equation [1] for the variable x

[1] 7x = 14

[1] 7x = 14 [1] x = 2

[1] 7x = 14 [1] x = 2 // By now we know this much :

x = 2

= 2 y = -5x/3+1/3

= 2 y = -5x/3+1/3// Use the x value to solve for y

= 2 y = -5x/3+1/3// Use the x value to solve for y y = -(5/3)(2)+1/3 = -3

= 2 y = -5x/3+1/3// Use the x value to solve for y y = -(5/3)(2)+1/3 = -3 Solution :

= 2 y = -5x/3+1/3// Use the x value to solve for y y = -(5/3)(2)+1/3 = -3 Solution : {x,y} = {2,-3}

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Answered by Anonymous
149

\large{\underline{\underline{\mathfrak{\green{\sf{Solution:-}}}}}}.

\large{\underline{\underline{\mathfrak{\sf{Given\:Here:-}}}}}.

  • \:5x\:-\:3y\:=\:13

  • \:2x\:+\:3y\:=\:1

\large{\underline{\underline{\mathfrak{\sf{Explanation:-}}}}}.

  • \:5x\:-\:3y\:=\:13.....(1)
  • \:2x\:+\:3y\:=\:1...... (2)

Multiply by 2 ×(1) - 2×(2)

  • \:10x\:-\:6y\:=\:26

  • \:10x\:+\:15y\:=\:5

Subtract its ,

___________________________

\implies\:-21y\:=\:21

\implies\:y\:=\frac{21}{-21}

\implies\boxed{\:y\:=\:1}

Keep, value of y in (1)

\implies\:5x\:-\:3\:×\:(-1)\:=\:13

\implies\:5x\:=\:-3\:+\:13

\implies\:5x\:=\:10

\implies\:x\:=\frac{10}{5}

\implies\boxed{\:x\:=\:2}

\large{\underline{\underline{\mathfrak{\sf{ANSWER:-}}}}}.

  • Value of \:x\:=\:2

  • Value of \:y\:=\:-1

\large{\underline{\underline{\mathfrak{\sf{Answer\:Checkup :-}}}}}.

Keep value of x and y in equation (2)

\implies\:2\:×\:2\:+\:3\:×\:-1\:=\:1

\implies\:4\:-\:3\:=\:1

\implies\:1\:=\:1

That's satisfies

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