5x+3y=3 and 3x+y=5 method of subsitution
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Answered by
1
5x+3y=3
3x+y=5
y=5-3x
5x+3(5-3x)=3
5x+15-9x=3
4x=12
x=3
9+y=5
y=-4
3x+y=5
y=5-3x
5x+3(5-3x)=3
5x+15-9x=3
4x=12
x=3
9+y=5
y=-4
Answered by
0
3x + y = 5
=> y = 5- 3x -------(1)
5x + 3y = 3 ------(2)
Substituting equation 1 into 2, we get
=> 5x + 3(5-3x) = 3
=> 5x + 15 - 9x = 3
=> - 4x = 3-15
=> - 4x = - 12
=> 4x = 12
=> x = 3
Now,
On putting the value of x in equation 1, we get
=> y = 5-3*3
=> y = - 4
=> y = 5- 3x -------(1)
5x + 3y = 3 ------(2)
Substituting equation 1 into 2, we get
=> 5x + 3(5-3x) = 3
=> 5x + 15 - 9x = 3
=> - 4x = 3-15
=> - 4x = - 12
=> 4x = 12
=> x = 3
Now,
On putting the value of x in equation 1, we get
=> y = 5-3*3
=> y = - 4
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