(5x÷4+3÷4)^3 expand using suitable identity
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(5x/4+3/4)^3
=(5x/4)^3+(3/4)^3+3(5x/4)(5x/4)3/4+3(5x
4)9/4
=(75x^3)/64+27/64+(225x^2)/64+135x/16
=(75x^3+225x^2+540x+27)/64
=(5x/4)^3+(3/4)^3+3(5x/4)(5x/4)3/4+3(5x
4)9/4
=(75x^3)/64+27/64+(225x^2)/64+135x/16
=(75x^3+225x^2+540x+27)/64
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