Question

5x + 4
5x-1
7x +3
7x-2​

Answer 1

Answer:

We have,

(7x – 2) / (5x – 1) = (7x +3)/(5x + 4) (7x – 2) / (5x – 1) – (7x +3)/(5x + 4) = 0

By taking LCM as (5x – 1) (5x + 4) ((7x-2) (5x+4) – (7x+3)(5x-1)) / (5x – 1) (5x + 4)

= 0

By cross-multiplying we get,

(7x-2) (5x+4) – (7x+3)(5x-1) = 0

Upon simplification,

35x2 + 28x – 10x – 8 – 35x2 + 7x – 15x + 3 = 0 10x – 5 = 0 10x = 5 x = 5/10 = 1/2

Now let us verify the given equation,

(7x – 2) / (5x – 1) = (7x +3)/(5x + 4)

By substituting the value of ‘x’ we get,

(7(1/2) – 2) / (5(1/2) – 1)

= (7(1/2) + 3) /(5(1/2) + 4) (7/2 – 2) / (5/2 – 1)

= (7/2 + 3) / (5/2 + 4) ((7-4)/2) / ((5-2)/2)

= ((7+6)/2) / ((5+8)/2) (3/2) / (3/2)

= (13/2) / (13/2) 1

= 1