Question

5x + 4y -4 =0
x - 20 = 12y
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Answer 1

ANSWER.

x - 20 = 12y

x - 20 = 12y x = 12y + 20

x - 20 = 12y x = 12y + 205x + 4y - 4 = 0

x - 20 = 12y x = 12y + 205x + 4y - 4 = 0 5(12y + 20) + 4y - 4 = 0

x - 20 = 12y x = 12y + 205x + 4y - 4 = 0 5(12y + 20) + 4y - 4 = 0 60y + 100 + 4y - 4 = 0

x - 20 = 12y x = 12y + 205x + 4y - 4 = 0 5(12y + 20) + 4y - 4 = 0 60y + 100 + 4y - 4 = 0 64y + 96 = 0

x - 20 = 12y x = 12y + 205x + 4y - 4 = 0 5(12y + 20) + 4y - 4 = 0 60y + 100 + 4y - 4 = 0 64y + 96 = 0 64y = -96

x - 20 = 12y x = 12y + 205x + 4y - 4 = 0 5(12y + 20) + 4y - 4 = 0 60y + 100 + 4y - 4 = 0 64y + 96 = 0 64y = -96 y = -96/64

x - 20 = 12y x = 12y + 205x + 4y - 4 = 0 5(12y + 20) + 4y - 4 = 0 60y + 100 + 4y - 4 = 0 64y + 96 = 0 64y = -96 y = -96/64 y = 1/2

x - 20 = 12y x = 12y + 205x + 4y - 4 = 0 5(12y + 20) + 4y - 4 = 0 60y + 100 + 4y - 4 = 0 64y + 96 = 0 64y = -96 y = -96/64 y = 1/2x - 20 = 12y

x - 20 = 12y x = 12y + 205x + 4y - 4 = 0 5(12y + 20) + 4y - 4 = 0 60y + 100 + 4y - 4 = 0 64y + 96 = 0 64y = -96 y = -96/64 y = 1/2x - 20 = 12y x - 20 = 12(1/2)

x - 20 = 12y x = 12y + 205x + 4y - 4 = 0 5(12y + 20) + 4y - 4 = 0 60y + 100 + 4y - 4 = 0 64y + 96 = 0 64y = -96 y = -96/64 y = 1/2x - 20 = 12y x - 20 = 12(1/2)x - 20 = 6

x - 20 = 12y x = 12y + 205x + 4y - 4 = 0 5(12y + 20) + 4y - 4 = 0 60y + 100 + 4y - 4 = 0 64y + 96 = 0 64y = -96 y = -96/64 y = 1/2x - 20 = 12y x - 20 = 12(1/2)x - 20 = 6 x = 20 + 6

x - 20 = 12y x = 12y + 205x + 4y - 4 = 0 5(12y + 20) + 4y - 4 = 0 60y + 100 + 4y - 4 = 0 64y + 96 = 0 64y = -96 y = -96/64 y = 1/2x - 20 = 12y x - 20 = 12(1/2)x - 20 = 6 x = 20 + 6 x = 26

x - 20 = 12y x = 12y + 205x + 4y - 4 = 0 5(12y + 20) + 4y - 4 = 0 60y + 100 + 4y - 4 = 0 64y + 96 = 0 64y = -96 y = -96/64 y = 1/2x - 20 = 12y x - 20 = 12(1/2)x - 20 = 6 x = 20 + 6 x = 26( x , y ) = ( 26 , 1/2 )

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