Question

5x+4y-4=0 x-20=12y solve by substitution method

Answer 1

x-20=12y

x=12y+20

now

5x+4y-4=0

5(12y+20)+4y=0

60y+100+4y=0

64y=-100

y=-100/64=25/16

x=105/4

Answer 2

hope this helps you....