Math, asked by Rudrappabiradar, 1 year ago

5x-6y+30=0;5x+4y-20=0 solve by graphical method

Answers

Answered by YuvRajDgr8
2
Solutions
Solving the following system:
{5 x - 6 y = -30 | (equation 1)
5 x + 4 y = 20 | (equation 2)
Subtract equation 1 from equation 2:
{5 x - 6 y = -30 | (equation 1)
0 x+10 y = 50 | (equation 2)
Divide equation 2 by 10:
{5 x - 6 y = -30 | (equation 1)
0 x+y = 5 | (equation 2)
Add 6 × (equation 2) to equation 1:
{5 x+0 y = 0 | (equation 1)
0 x+y = 5 | (equation 2)
Divide equation 1 by 5:
{x+0 y = 0 | (equation 1)
0 x+y = 5 | (equation 2)
Collect results:
Answer:
x = 0
y = 5
Attachments:
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