Question

5x+7y=17 ; 3x-2y=4 solve​

Answer 1

$\huge\underline\mathfrak{Answer-}$

$\huge\boxed{x=2}$

$\huge\boxed{y=1}$

$\huge\underline\mathfrak{Explanation-}$

By using elimination method,

5x + 7y = 17 ______(1)

3x - 2y = 7 _______(2)

Multiply, equation (1) by 3 and equation (2) by 5.

$\bf\red{(5x+7y=17)}$ × 3

$\implies$ 15x + 21y = 51 _____(3)

$\bf\red{(3x-2y=4)}$ × 5

$\implies$ 15x - 10y = 20 _____(4)

Subtract equation (4) from (3),

$\cancel{15x}$ + 21y = 51

$\cancel{-15x}$(+) - 10y = (-)20

_________________

31y = 31

$\implies$ y = $\dfrac{31}{31}$

$\implies$ y = 1

Now, put the value of y in eq (1),

5x + 7(1) = 17

$\implies$ 5x + 7 = 17

$\implies$ 5x = 17 - 7

$\implies$ 5x = 10

$\implies$ x = $\dfrac{10}{5}$

$\implies$ x = 2

Answer 2

Answer:

X = 2 and Y = 1

Step-by-step explanation: