5x+y=26,
3y+y=16
solve the following pair of linear equation by the substitution method and cross multiplication method
Answers
Answered by
1
5 X+Y=26
3 Y+Y=16
soln
3 Y+Y=16
4 Y/4=16/4
Y =4
5 X +4=26
5 X=26-4
5 X/5=22/5
X=4.4
3 Y+Y=16
soln
3 Y+Y=16
4 Y/4=16/4
Y =4
5 X +4=26
5 X=26-4
5 X/5=22/5
X=4.4
Similar questions