5x2+33xy-14xy2 factrize
kaviyadharshine:
is it a correct question.
X inbetween 5 & 2 represent variable or multiple symbol
Answers
Answered by
27
5x² + 33xy - 14y²
= 5x² + 35xy - 2xy - 14y²
= 5x( x + 7y) - 2y( x + 7y)
= (5x - 2y)(x + 7y)
hence, (5x - 2y) and (x + 7y) are the factors of given polynomial.
= 5x² + 35xy - 2xy - 14y²
= 5x( x + 7y) - 2y( x + 7y)
= (5x - 2y)(x + 7y)
hence, (5x - 2y) and (x + 7y) are the factors of given polynomial.
Answered by
5
[tex]5x^2 + 33xy - 14y^2\\= 5x^2 + 35xy - 2xy - 14y^2\\= 5x( x + 7y) - 2y( x + 7y) \\
= (5x - 2y)(x + 7y)
[/tex]
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