5y^2+7y find the zeros of the quadratic polynomial.
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Given quadratic equation,
➙ 5y² + 7y
Let,
- a = 5
- b = 7
- c = 0
➢ Sum of the zeroes : α + ß = -b/a = -7/5
➢ Product of the zeroes : αß = c/a = 0/5 = 0
Therefore, the zeroes are " -7/5 " & " 0 ".
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