5y/ 2-x/3=8and y/2 + 5x/3=12
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Hi!
Answer=>
1 Solve for x in 5× y/2-x/3=8
x=-3(8-5y/2)
2 Substitute x=-3(8-\frac{5y}{2})x=−3(8−2/5y ) into y/2+5×x/3=12
13y-40=12
3 Solve for yy in 13y-40=1213y−40=12
y=4y=4
4 Substitute y=4y=4 into x=-3(8-5y/2x=−3(8−2/5y )
5 Therefore,
x=6
y=4
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