Math, asked by TbiaSupreme, 1 year ago

5y + 4 = 20 : Check if the equation has ‘2’ as solution.

Answers

Answered by Anonymous
1
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5 y + 4 = 20

5 ( 2 ) + 4 = 20

10 + 4 = 20

14 = 20

Value doesn't satisfies the equation !!

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Answered by mysticd
0
Given linear equation in one variable

y is ,

5y + 4 = 20 ---( 1 )

Substitute y = 2 in Equation ( 1 ), we get

5 × 2 + 4 = 20

=> 10 + 4 = 20

=> 14 = 20 [ False ]

Therefore ,

y = 2 is not a solution of 5y + 4 = 20

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