5y + 4 = 20 : Check if the equation has ‘2’ as solution.
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1
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5 y + 4 = 20
5 ( 2 ) + 4 = 20
10 + 4 = 20
14 = 20
Value doesn't satisfies the equation !!
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0
Given linear equation in one variable
y is ,
5y + 4 = 20 ---( 1 )
Substitute y = 2 in Equation ( 1 ), we get
5 × 2 + 4 = 20
=> 10 + 4 = 20
=> 14 = 20 [ False ]
Therefore ,
y = 2 is not a solution of 5y + 4 = 20
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y is ,
5y + 4 = 20 ---( 1 )
Substitute y = 2 in Equation ( 1 ), we get
5 × 2 + 4 = 20
=> 10 + 4 = 20
=> 14 = 20 [ False ]
Therefore ,
y = 2 is not a solution of 5y + 4 = 20
••••
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