Math, asked by HrishiHindocha, 1 year ago

5y²+5-10 (factorise) ​

Answers

Answered by ahanatarafder06
1

5y^2+5-10 = 5y^2-5

=5(y^2-1)

=5(y^2-1^2)

=5(y+1)(y-1)

The correct answer is 5(y+1)(y-1).

Answered by Diabolical
0

Answer:

The answer will be 5(y-1)(y+1).

Step-by-step explanation:

We have given that,

                                 =   5y^2 + 5 - 10;

From here,          =   5y^2 - 5;

                            =   5(y^2 - 1);

Now, we had studied an identity in previous classes that;

                            = (x-y)(x+y);

                           = x^2 - y^2;

Hence, from above identity, we can write our equation as;

                        = 5(y^2-1);

                         = 5{(y)^2 - (1)^2};                 {from above identity}

                        = 5(y-1)(y+1);

That's all.

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