Question

Find the values of a and b if (3+√2)/(3-√2)=a+b√2

Answer 1

Answer:

$(3+\sqrt{2}) (3-\sqrt{2}) =a+b\sqrt{2} \\=>9-2=a+b\sqrt{2} \\Therefore, a=9,b=-\sqrt{2}$

Step-by-step explanation:

Answer 2

Answer:

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Step-by-step explanation:

$\frac{(3+\sqrt{2}}{3-\sqrt{2} }$

Rationalise this

$\frac{11+\sqrt{2} }{7}$

on equating we get

$a= \frac{11}{7} \\b= \sqrt[6]{2}$