Question

6.022 x 10^20 molecules of urea are present in 100ml solution. The concentration of urea solution is.............

Answer 1

Answer: 10⁻²M IS THE ANSWER.

Explanation:

NUMBER OF MOLES=NO OF MOLECULES/AVAGADRO NUMBER

                                   =6.022×10²⁰/6.022×10²³

                                   =10⁻³ moles

THEN CONCENTRATION=NO OF MOLES×1000/VOLUME (ml)

                                          =10⁻³ moles×1000/100=10⁻²M

SO CONCENTRATION OF UREA SOLUTION IS 10⁻²M.

HOPE IT HELPS YOU....................

THANK YOU.

Answer 2

Answer:

10^-2 M

Explanation:

1 mole urea contains 6.022 × 10^23 molecules

here no. of moles = 6.022 x 10^20/6.022 × 10^23

=10^-3 moles

volume of solution is 0.1 litre.

Molarity = no. of moles/volume of solution in litre

= 10^-3/0.1

=10^-2 M