Question

6.022x10^22 molecules of a compound X has mass 10 g. what is the molarity of solution containing 5 g of X in 2 litre solution. answer as P (where M = Px10^-3 mole/lit) ​

Answer 1

Answer:

P= 250

Explanation:

given 6.022x10^22 molecules has a mass of 10gms

implies 1 mole of substance X has 10gms

now 5 gms of a substance x means 1/2 mole

Molarity(M)= no.of moles of solute/volume of the solution

M=(1/2)×(1/2)

M=0.25mole/lit

M=250×10^-3 mole/lit

Answer 2

It has given that 6.022 × 10²² molecules of a compound X has mass 10g.

we have to find the molarity of solution containing 5g of X in 2 litre solution.

solution : 6.022 × 10²² molecules of a compound X has mass 10g.

so 5g of compound X contains 3.011 × 10²² molecules.

no of moles of X = (no of molecules of X)/(Avogadro's number)

= (3.011 × 10²²)/(6.022 × 10²³)

= 1/20

= 0.05

now Molarity = (no of moles)/(volume in litre)

= 0.05/2 = 0.025

but given, molarity M = P × 10¯³ mol/L .....(1)]

here M = 0.025 = 25 × 10¯³ mol/L

on comparing to eq (1) we get P = 25

Therefore the value of P is 25