Question

6
1
14
a
-10
The HCF of two numbers is 3 and their com is
1449. If one of the nomber is 161, the other
nomber is​

Answer 1

Answer:

cvfdujhxzftkmbdfguiuhfdetgfsdttuuhhg

Answer 2

SHORT WAY :-

as we know,

HCF * LCM = product of numbers

23*1449 = 161*x ( let the other no. be x )

23*1449/161=x

207 = x

hence, the other no. is 207

LONG WAY:-

let a&b be two numbers

so,Lcm of a&b= 1449

and HCF of a&b =23

and let one number be a so, a=161

according to formula H=axb/L

23=161xb/1449

1449x23/161=b

therefore b=207

so, another number is 207.