6×10^20molecules of Glucose dissolved in 200ml of H2O.
I will mark them as bainlist,
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Molarity (molL−1)=Moles of soluteVolume of solution)(in L)
6.02×1023 molecules of urea = 1 Mole
∴6.02×1020 molecules of urea
=6.02×10206.02×1023=1×10−3mol
200ml=0.20L
Molarity =1×10−30.20=0.02M
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