Question

6,11,16 is an AP. find the sum of first 15 terms and next 15 terms​

Answer 1

Answer:

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Answer 2

$a = 6$

$d = 5$

1.Sum of first 15 terms

$sn = \frac{n}{2} (2a + (n - 1)d)$

$s15 = \frac{15}{2} (2 \times 6 + 14 \times 5)$

$= \frac{15}{2} (12 + 70)$

$= \frac{15}{2} \times 82$

$= 615$

.....(i)

.

2.Sum of next 15 terms

=Sum of first 30 terms - Sum of first 15 terms

• Sum of first 30 terms =

$= \frac{30}{2} (2 \times 6 + 29 \times 5)$

$= 15(12 + 145)$

=2355.........(ii)

Now,

Subtract

$= 2355 - 615$

$= 1740$

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