English, asked by himansu7681, 1 year ago

[(6/11)^7y+8]÷[(121/36)^y-2]=(1331/216)^y

Answers

Answered by loveyshah2010

6

(6/11)^7y+8 / (6/11)^-2y+4 = (6/11)^-3y

(6/11)^9y+4 = (6/11)^-3y

9y+4 = -3y

12y = -4

y = -1/3

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