Question

6,12,21,36,56,81 FIND THE WRONG NUMBER

Answer 1

Answer:

$\huge{\boxed{\boxed{\sf{56}}}}$

Step-by-step explanation:

$\huge{\boxed{\boxed{\underline{\sf{SOLUTION-}}}}}$

$1)6 \: divides \: by \: 2 \: and \: 3 \\ 2)12 \: divides \: by \: 2 \: and \: 3 \\ 3)21 \: divides \: by \: only \: 3 \\4) 36 \: divides \: by \: 2 \: and \: 3 \\ 5)56 \: divides \: by \: 2 \: but \: not \: by \: 3 \\6)81 \: divides \: by \: only\:from \: these \: 6 \: points \\ our \: contradiction \: gets \: that \: \\ (1)all \: the \: numbers \: are \: divide \: by \: 2 \: except \\ 2 \: numbers \: that \: is \: 21 \: and \: 81 \\ (2)all \: numbers \: are \: divided \: by \: 3 \\ except \: 56 \\ > > so \: we \: choose \: 2nd \: option \:$

$\huge{\boxed{\boxed{\sf{56}}}}$