6 15) If ö is ' any point inside the "rectangle IABCD such that OB=2cm, OD 3 then OC=? OA= 1cm
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Given, ABCD is a rectangle. O is any point inside the rectangle.
Construction: Construct perpendiculars OP, OQ, OR, OS on each side.
Now, OA2+OC2=(AS2+OS2)+(OQ2+QC2) (Considering right triangles ASO and COQ)
But AS=BQ and QC=SD, Therefore,
OA2+OC2=(BQ2+OS2)+(OQ2+SD2)
OA2+OC2=(BQ2+OQ2)+(OS2+SD2)
OA2+OC2=OB2+OD2 (Considering right triangles OSD and OBQ)
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I hope it will help you.
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