Question

(6√2/√3+√6)-(4√3/√6+√2)+(2√6/√2+√3)​

Answer 1

Step-by-step explanation:

Solution is in theAttachment.

First rationalize the denominator of each term by multiplying its conjugate in both the numerator and denominator and simplify it.

Conjugate of a first term (√2+√3) is

(√2-√3)

Conjugate of second term (√6+√3) is (√6-√3)

Conjugate of third term (√6+√2) is (√6-√2)

In denominator FORMULA used=

(a+b)(a-b)= a² - b²

=========================================================°======