(6/2√3-√6) +(√6/√3+√2)-4√3/√6-√2
Answers
Answered by
8
Answer:
0
Step-by-step explanation:
6/2√3-√6 = 6*(2√3+√6)/(12-6) = 2√3 +√6..(1)
√6/√3 +√2 = √6*(√3-√2)/(3-2) = √18 -√12 =
3√2-2√3 ..(2)
4√3/√6-√2 = 4√3*(√6+√2)/(6-2)= 4√3/4 *(√6+√2) =√18+√6 = 3√2+√6
(1)+(2)-(3) => 2√3+√6+3√2-2√3 -3√2-√6 => 0
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Answered by
4
Answer:
6/2√3-√6=6×(2√3+√6)/(12-6)=2√3+√6..(1)
√6/√3 +√2 =√6×(√3-√2)/(3-2)=√18-√12
=3√2-2√3..(2)
4√3/√6-√2=4√3×(√6+√2)/(6-2)=4√3/4×(√6+√2)=√18+√6=3√2+√6
(1)+(2)-(3)=>2√3+√6+3√2-2√3-3√2-√6
So the answer is 0.
Hope it helps.
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