Question

(6/2√3-√6) +(√6/√3+√2)-4√3/√6-√2​

Answer 1

Answer:

0

Step-by-step explanation:

6/2√3-√6 = 6*(2√3+√6)/(12-6) = 2√3 +√6..(1)

√6/√3 +√2 = √6*(√3-√2)/(3-2) = √18 -√12 =

3√2-2√3 ..(2)

4√3/√6-√2 = 4√3*(√6+√2)/(6-2)= 4√3/4 *(√6+√2) =√18+√6 = 3√2+√6

(1)+(2)-(3) => 2√3+√6+3√2-2√3 -3√2-√6 => 0

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Answer 2

Answer:

$\fbox a \: \fbox n \: \fbox s \: \fbox w \: \fbox e \: \fbox r$

6/2√3-√6=6×(2√3+√6)/(12-6)=2√3+√6..(1)

√6/√3 +√2 =√6×(√3-√2)/(3-2)=√18-√12

=3√2-2√3..(2)

4√3/√6-√2=4√3×(√6+√2)/(6-2)=4√3/4×(√6+√2)=√18+√6=3√2+√6

(1)+(2)-(3)=>2√3+√6+3√2-2√3-3√2-√6

$\longrightarrow \: 0$

So the answer is 0.

Hope it helps.

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