Question

√6/√2+√3 rationalise the denominator

Answer 1

multiply both sides of the fraction by (root2-root3)
the numerator will be root12-root18
the denominator will be (root2)sq.-(root3)sq. {by applying identity a sq.-b sq.}
then again simplifying the fraction:
(2 root3 - 3 root2)/ -1
i.e.
-2 root3 + 3 root2
= 3 root2 - 2 root3
which is the answer

Answer 2

√4 is the answer of following question