Math, asked by ra9emasansi, 1 year ago

6 2x-1 -(36) x-1 =6480 Find the value of x.


zeen: Is it 62x or 6(2)x?

Answers

Answered by ARoy
11
6²ˣ⁻¹-36ˣ⁻¹=6480
or, 6²ˣ⁻¹-(6²)ˣ⁻¹=6480
or, 6²ˣ⁻¹-6²ˣ⁻²=6480
or, 6²ˣ(6⁻¹-6⁻²)=6480
or, 6²ˣ(1/6-1/36)=6480
or, 6²ˣ(6-1)/36=6480
or, 6²ˣ×5/36=6480
or, 6²ˣ=6480×36/5
or, 6²ˣ=1296×36
or, 6²ˣ=6⁴×6²
or, 6²ˣ=6⁶
∴, 2x=6
or, x=3
Answered by jay27727
3

Answer:

62x-1_36X-1=6480

or, 62x-1-(62)x-1=6480 or, 6?x-1-62x-2-6480

or, 62X(6-9-6-2)=6480

or, 62X(1/6-1/36)=6480

or, 62x(6-1)/36=6480 or, 62xx5/36=6480

or, 6-X=6480x36/5

or, 62x=1296x36

or, 62x=64x62

or, 62 x-66

, 2x=6

or, x=3

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