Math, asked by millscharle1, 2 months ago

6(2x – 11) + 15 = 3x + 12 Part A: Write the steps you will use to solve the equation, and explain each step. (6 points) Part B: What value of x makes the equation true? (4 points)

Answers

Answered by hiteshrawat370
18

Answer:

fog lights on the phone with my mom is going to be a good day at work and I don't

Step-by-step explanation:

he was like I said I was just wondering if you want to be a good day at work and I don't know what I want

Answered by LaCheems
53

{\huge{\boxed{\sf{\color{lightpink}{Requ}{\color{magenta}{ired}{\color{orchid}{Ans}{\color{purple}{wer}}}}}}}}

To Solve:

  • Solve: 6(2x – 11) + 15 = 3x + 12
  • Part A: Write the steps you will use to solve the equation, and explain each step
  • Part B: What value of x makes the equation true?

Solⁿ:

{ \sf{ \pink{Part \:  \:  A: }}}

{ \sf{6(2x – 11) + 15 = 3x + 12}} \\  \\ { \sf{   \geqslant   \: do \:  \: algebric \:  \: multiplication :}} \\  \\ { \sf{12x - 66 + 15 = 3x + 12}} \\  \\ { \sf{ \geqslant  \: combine \:  \: the \:  \: like \:  \: terms : }} \\  \\ { \sf{12x - 51 = 3x + 12}} \\  \\    { \sf{12x - 3x = 12 + 51}} \\  \\{ \sf{ after \:  \: solving \:  \: divide \:  \: the \: terms }} \\ { \sf{and \:  \: get \:  \: suitable \:  \: value}}  \\  \\  { \sf{9x = 63}} \\  \\ { \sf{ x =  \frac{ \cancel{63}} { \cancel{9}}}}\\  \\ { \boxed{\sf{ \: x = 7}}}

{ \sf{ \pink{Part \:  \:  B :}}}

{ \sf{  \purple{taking \:  \: the \: value \:  \: of \:  \: x \:  \:a s \:  \: 9.}}}

{ \sf{ \purple{ will \: \: make \:  \: the \: equation \:  \: { \bold{ true.}}}}}

HOPE IT HELPS

MARK BRAINLIEST PLS :)

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