Question

koi meri help karega plssssszzzz.....​

Answer 1

Answer:

$sin(n^{o} ) = cos(180 - \frac{\pi}{3} ) \\ \\ = > cos(90 - n) = cos(180 - \frac{\pi}{3} ) \\ \\ = > 90 - n = 180 - \frac{\pi}{3} \\ \\ \\ = > \frac{\pi}{3} + 90 - 180 = n \\ \\ \\ = > n = 60 + 90 - 180 = - 30$

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Answer 2

Answer:

π/3

Step-by-step explanation:

put the value of cos 2π/3 then u will get ur answer