6÷3+√2-√5 rationalize the denominator
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6/3+√2-√5
6(√2-√5) /3+√2-√5(√2-√5)
6(√2-√5)/3+2+5
6√2-6√5/10
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Answer:
6/3+√2-√5
6(√2-√5) /3+√2-√5(√2-√5)
6(√2-√5)/3+2+5
6√2-6√5/10
this fraction is obtained after rationalizing
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