Question

please solve it step by step ​

Answer 1

Answer:

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Answer 2

Answer:

Given :- < ACB = 4y

To find :- x and y

Solution :- In triangle ACD

<CAD + < C + < D =180°( Angle sum property)

y + 4y + 105° = 180°

5y + 105° = 180°

5y = 180° - 105°

5y = 75°

$y = \frac{75}{5} \\ y = 15$

In triangle ABC

< A + < B + < C = 180°( angle sum property )

(x+ y ) + 75° + 4y = 180°

x + 15 + 75° + 4 × 15 = 180°

x + 90° + 60° = 180°

x + 150° = 180°

x = 180° - 150°

x = 30°

< A = x + y

= 30 + 15

= 45°

< B = 75°

< C = 4y

= 4 × 15

= 60°

I hope it will help you out.