Math, asked by ishansherekar, 3 days ago

6(3*4/6)+13[3-2{4+2-(6*2-3*5+6-2*3)}]

Answers

Answered by misscutie94
2

Answer:

\huge\colorbox{cyan}{Solution}

\longrightarrow  6\bigg(3 \times \dfrac{4}{6}\bigg) + 13[3 - 2\{4 + 2 - (6 \times 2 - 3 \times 5 + 6 - 2 \times 3)\}]

\Rightarrow  6\bigg(\dfrac{12}{6}\bigg) + 13[1 \{6 - (12 - 15 + 6 - 6)\}]

\Rightarrow  6 (2) + 13[1 \times 6 - (- 3)]

\Rightarrow  12 + 13 \times 1\times 6 + 3

\Rightarrow  12 + 78 + 3

\Rightarrow  93

\therefore  The\: answer\: of\: this\: question\: is\: 93\:

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