6√3x^2+7x-√3=0 solve by factorisation
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Step-by-step explanation:
6√3x^2+9x-2x-√3=0
3√3x(2x+√3)-1(2x+√3)=0
(2x+√3)(3√3x-1)=0
so x = 1/(3√3)
and x= -√3/2
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