Math, asked by rosemarydsouza1718, 9 days ago

6√3x^2+7x-√3=0 solve by factorisation​

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Answered by rajunaga110
0

Step-by-step explanation:

6√3x^2+9x-2x-√3=0

3√3x(2x+√3)-1(2x+√3)=0

(2x+√3)(3√3x-1)=0

so x = 1/(3√3)

and x= -√3/2

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