Question

6-4√2÷6+4√2*6-4√2÷6-4√2​

Answer 1

Answer:

Answer

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RAJdba

rationalising factor = 6-4√2

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Answer

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snehitha2

(6-4√2)/(6+4√2) × (6-4√2)/(6-4√2)

= (6-4√2)²/(6²-(4√2)²)

= {6²+(4√2)² - 2(6)(4√2)}/(36-32)

Answer 2

ANSWER :-

Rationalise the denominator:

(6 - 4√2)/(6 + 4√2)

Multiply by 6 - 4√2 both numerator and denominator.

$\frac {6 - 4 \sqrt2}{6 + 4 \sqrt2}$

= $\frac {( 6 - 4 \sqrt2 ) \ ( 6 - 4 \sqrt2)}{( 6 + 4 \sqrt 2 ) \ (6 - 4 \sqrt2 )}$

= $\frac {( 6 - 4 \sqrt2)²}{36 - 32}$

= $\frac {36 - 48 \sqrt2 + 32}{4}$

= $\frac {68 - 48 \sqrt2}{4}$

= $\frac {4 ( 17 - 12\sqrt2 ) }{4}$

= 17 - 12$\sqrt2$