Question

(6+ 5 root 3) - (4 + root 75) is rational or irrational or negative integer​

Answer 1

Answer:

Rational Integer

Step-by-step explanation:

$6 + 5 \sqrt{3} - (4 + \sqrt{75} )$

$= 6 + 5\sqrt{3} - 4 - \sqrt{75}$

$= 2 + 5 \sqrt{3} - 5\sqrt{3}$

$= 2$

2 is a rational no.

Therefore,

(6+ 5 root 3) - (4 + root 75) is a RATIONAL INTEGER.

NOTE: In the step no. 3 we have written root 75 as 5root 3 by converting it into simpler form. This step is very very important.

Hope It Helps