Question

6(6x+1)÷3+6*1=6(x-3)÷6

Answer 1

$\frac{6(6x + 1)}{3} + 6 \times 1 = \frac{6(x - 3)}{6} \\ = > \frac{36x + 6}{3} + 6 = \frac{6x - 18}{6} \\ = > \frac{36x + 6 + 6 \times 3}{3} = \frac{6x - 18}{6} \\ = > \frac{36x + 6 + 18}{3} = \frac{6x - 18}{6} \\ = > \frac{36x + 24}{3} = \frac{6x - 18}{6} \\ = > 6(36x + 24) = 3(6x - 18) \\ = > 216x + 144 = 18x - 54 \\ = > 216x - 18x = - 54 - 144 \\ = > 198x = - 198 \\ = > x = \frac{ - 198}{198} \\ = > x = - 1$

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