a bag has 4 red ball and 2 green ball .what is probability of getting red ball
Kashish892004:
It should be 2 upon 3
Answers
Answered by
5
A bag had 4 red ball , 2 green ball.
Let A be the events of red ball,
n(A) = 4 .
Let B be the events of green ball ,
n(B) = 2 .
Total balls = 2 + 4 = 6 .
Now, Probability of getting Red balls = Number of probable outcomes / Total outcomes = 4/6 = 2/3 .
Probability of getting Green balls = Number of probable outcomes / Total outcomes = 2/6 = 1 /3 .
Let A be the events of red ball,
n(A) = 4 .
Let B be the events of green ball ,
n(B) = 2 .
Total balls = 2 + 4 = 6 .
Now, Probability of getting Red balls = Number of probable outcomes / Total outcomes = 4/6 = 2/3 .
Probability of getting Green balls = Number of probable outcomes / Total outcomes = 2/6 = 1 /3 .
Answered by
1
hello adi :))))
hello :))
=======================
==========================
nice question bro..
------------------------------------------------------
total no. of balls= red+green balls
=6
so prbablity of getting a red ball= p(rb)= red balls/toatal no. of balls.
so we putting here..
====> 4/6
====>>2/3 ----> answer :)))
hope it helps you..
======================================
================================
all the best :))
===================================
thanks :))
--------------------------------------------------------
hello :))
=======================
==========================
nice question bro..
------------------------------------------------------
total no. of balls= red+green balls
=6
so prbablity of getting a red ball= p(rb)= red balls/toatal no. of balls.
so we putting here..
====> 4/6
====>>2/3 ----> answer :)))
hope it helps you..
======================================
================================
all the best :))
===================================
thanks :))
--------------------------------------------------------
Similar questions