Ram built a cubical water tank with lid for his house ,with each edge 2m .he gets the outer surface of the tank excluding the basecovered with square tiles of side 25cm .find how much he would spend for the tiles ,if one dozen of tiles costs him Rs 480.
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Answered by
8
side of tank = 2 m
lateral surface area = 4 side × side
= 16msquare
side of tile= 25 cm = 0.25m
area of 1 tile = 0.0625msquare
no. of tiles = l.s.a. / area of tile = 16/ 0.0625
= 256 tiles
cost of 12 tiles = 480rs.
cost if 1 tile= 480/ 12 = 40rs.
cost of 256 tiles = 40×256 = 10240 rs.
if helpful then mark as brainliest
lateral surface area = 4 side × side
= 16msquare
side of tile= 25 cm = 0.25m
area of 1 tile = 0.0625msquare
no. of tiles = l.s.a. / area of tile = 16/ 0.0625
= 256 tiles
cost of 12 tiles = 480rs.
cost if 1 tile= 480/ 12 = 40rs.
cost of 256 tiles = 40×256 = 10240 rs.
if helpful then mark as brainliest
Answered by
1
320000 is it right
explanation
5a^2 = 20 m^2
so 200000cm
no of tiles = 200000/25
= 8000 tiles
12 tiles cost = 480
1 tile 480/12
8000 tiles cost 480 * 8000/12
320000
explanation
5a^2 = 20 m^2
so 200000cm
no of tiles = 200000/25
= 8000 tiles
12 tiles cost = 480
1 tile 480/12
8000 tiles cost 480 * 8000/12
320000
Thanks
Similar questions
Given, the base of water tank is not covered with tiles, So, five outer faces will be covered by squares tiles.
∴ Surface area of water tank =5a2 = 5(200)2= 200000cm2
side of square tile = 25 cm
So, Area of each square tile = (side)2 = 252 = 625 cm2.
Number of square tiles required = (Area of water tank) / (Area of each square tile
= 200000/ 625 = 320.
Now, Given, Cost of 1 dozen tiles = Rs 480.