Question

{(6/7)^-1 -(1/6)^-1}÷(29)^-1. ​

Answer 1

$(( { \frac{6}{7} )}^{ - 1} - ( { \frac{1}{6} )}^{ - 1} ) \div ( { \frac{29}{1} )}^{ - 1} \\ \\ = (( { \frac{7}{6} )}- ( { 6)} ) \div ( { \frac{1}{29} )} \\ \\ = \frac{ - 29}{6} \times \frac{29}{1} \\ \\ = \frac{ - {(29)}^{2} }{6}$