Question

а6– 7а3 – 8
factorize​

Answer 1

Answer:

=a^6 - 7a^3 - 8

=a^6 - 8a^3 - a^3 - 8

=a^3(a^3 - 8) - 1(a^3 - 8)

=(a^3 - 8) (a^3 - 1)

Answer 2

let a3=x

:the equation becomes

x^2-7x-8

=x^2-8x+1x-8

=x(x -8)+1(x-8)

=(x+1)(x-8)

putting the value of x

=(a^3+1)(a^3-8)

application of formula

(A^3+B^3)=(A+B)(A^2+B^2-AB)

(A^3-B^3)=(A-B) (A^2-B^2+AB)

we get.

(a+1)(a-2)(a^2-a+1)(a^2+2a+4).....is answer

plz follow me....