Question

6-9y-27y^2 factories​

Answer 1

Answer:

Step-by-step explanation:

27y²-9y-6=0

dividing each term by 3

u get

-9y²-3y-2=0

9y²+3y+2=0

9y²+6y-3y+2=0

3y(3y+2)-1(3y+2)=0

y=-2/3

and y=1/3 is the answer of this question

Answer 2

Step-by-step explanation:

$6 - 9y - 27 {y}^{2} \\ = - 27 {y}^{2} - 9y + 6 \\ = - 3 (9 {y}^{2} + 3y - 2) \\ = - 3 (9 {y}^{2} + (6 - 3)y - 2) \\ = - 3 (9 {y}^{2} + 6y - 3y - 2) \\ = - 3 (3y(3y + 2) - 1(3y + 2)) \\ = - 3(3y + 2)(3y - 1)$