Question

6. A and B can finish a piece of work in 16 days and 12 days respectively. A started the work
and worked at it for 2 days. He was then joined by B. Find the total time taken to finish the
work.​

Answer 1

Answer:

Average work done = 48 (LCM of 16 and 12)

Work done by A in 1 day = 48/16 = 3

Work done by B in one day = 48/12 = 4

A did the work for 2 days = 3 x 2 = 6

Work remaining is 42.

If A and B works together = 3 + 4 = 7

Time taken to work together = 42/7 = 6

Total days taken = 6 + 2 = 8 days

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