Question

6. A bicyclist is traveling at +25 m/s when he begins to decelerate at -4 m/s
How fast is he traveling after 5 seconds?​

Answer 1

Answer:

u= 25 m/s

r=-4m/s

( r=retardation same word of decelerate)

t=5sec

s=?

s=ut +1/2 at ^2

s=25×1/2×(-4)^2

s=25×1/2×4

s=25/2×4

s=25×2

s=50m/s^-2

Answer 2

The speed of the bicyclist after 5 seconds is 5 m/s.

Explanation:

Initial speed of bicyclist, u = +25 m/s

Deceleration of the bicyclist, a = -4 m/s²

Let v is the speed of bicyclist after 5 seconds. It can be given by :

v = u + at

v = 25 + (-4) × 5

v = 5 m/s

So, the speed of the bicyclist after 5 seconds is 5 m/s.

Learn more,

Kinematics

https://brainly.in/question/5983384