Question

6.
A block of mass m lies on a rough surface of co-efficient of friction u. A
force F is applied on it at an angle theta to the horizontal as shown, and the block is at rest. The frictional force acting on the block will be
(A) F cos theta
(B) umg + F sin theta)
(C) (mg - F sin theta)
(D) umg​

Answer 1

Answer:

A.

the horizontal component of the. force F is Fcostheta.

that's why frictional force become Fcostheta

Answer 2

Explanation:

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