6. A can do a piece of work in 6 hours while B alone can do it in 16 hours. If A, B and C working together can finish it in 8 hours, in how many hours can Calone finish the work?
Answers
Step-by-step explanation:
The question is wrong.
When A does the work in 6 hours and B does it in 16 hours, why should A, B and C, three of them together take 8 hours to finish the work. It should be less than 6 hours!
A does 1/6th of the work in an hour, while B does 1/16th of the work in an hour. A, B and C do 1/8th of the work in an hour.
So C does (1/8) - (1/6) - (1/16) = (6/48) - (8/48) - (3/48) = (6–8–3)/48 = -11/48th part of the work in an hour. So he will complete the work in -48/11 = -4 and 4/11 th hour.
A negative answer for C as (-4 and 4/11th hour) is impossible. It means C is a hindrance to the work and he is obstructing A and B from doing their work!
Answer:
the question has a mistake or is incomplete
Step-by-step explanation:
When A does the work in 6 hours and B does it in 16 hours, why should A, B and C, three of them together take 8 hours to finish the work. It should be less than 6 hours!
A does 1/6th of the work in an hour, while B does 1/16th of the work in an hour. A, B and C do 1/8th of the work in an hour.
So C does (1/8) - (1/6) - (1/16) = (6/48) - (8/48) - (3/48) = (6–8–3)/48 = -11/48th part of the work in an hour. So he will complete the work in -48/11 = -4 and 4/11 th hour.
A negative answer for C as (-4 and 4/11th hour) is impossible. It means C is a hindrance to the work and he is obstructing A and B from doing their work!
so this is a nonsense question