Question

(6) A card is selected at random from well-shuffled pack of 52 cards. Find the
probability that the selected card is (i) a face card (ii) of diamond (iii) not an ace (iv)
is an ace of black colour.

Answer 1

Hiii...

Answer:

(i) a face card - 3/13

(ii) of diamond - 1/4

(iii) not an ace - 12/13

(iv)

is an ace of black color - 1/26

Step-by-step explanation:

Total number possible outcomes = 52

(i) Total number of face card = 12

  # P(face card) = 12/52=3/13

(ii)  Total number of diamond cards = 13

 # P(diamond cards) = 13/52 = 1/4

(iii) Total number of ace = 4

  # P(an ace) = 4/52=1/13

P(E) + P(not E) = 1

P(ace) + P(not an ace) = 1

1/13 + P(not an ace) = 1

#P(not an ace) = 1 - 1/13 = 13-1/13 = 12/13

(iv)  Total number of ace of black color = 2

  # P(ace of black color) = 2/52=1/26

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