Question

6. A chord of a circle is equal to the radius of the circle. Find the angle subtended by the
chord at a point on the major arc and also on the minor arc.
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Answer 1

Answer:

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Answer 2

Step-by-step explanation:

we have to find angle ADB and angle AEB

construction = who is centre and R is radius and given that chord is equal to radius of circle

now in angle A O B we have

AO=OB=BA ( it is given that chord is equal to radius of circle )

so ,

angle AOB=2 angle ADB

( the angle subtended by an Arc of a circle at the centre is double the angle subtended by it at any point on the remaining part of circle )

then angle = 30°

so,

angle AEB= 1/2( reflex angle AOB)

= 1/2 (360° - 60° )

= 150°

therefore,

angle AOB = 30° and angle AEB = 150°

hence, the angle subtended by the chord at a point on the minor Arc is 150 degree and also at the point on the major Arc is 30 degree