6. A chord of a circle of radius 15 cm subtends an angle of 60° at the centre. Find the areas
of the corresponding minor and major segments of the circle.
(Use A = 3.14 and 13 = 1.73)
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area of sector=60/360×22/7×15×15
=55×15/7=117.8
=117.7-(225/2×√3/2)
=117.7-225×1.73/4
=81.6/4=20.4cm^2
area of major sector =(πr^2)-20.4cm^2
=706.5-20.4
=686.1cm^2
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