Question

6. A chord of a circle of radius 15 cm subtends an angle of 60° at the centre. Find the areas
of the corresponding minor and major segments of the circle.
(Use A = 3.14 and 13 = 1.73)​

Answer 1

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Answer 2

area of sector=60/360×22/7×15×15

=55×15/7=117.8

=117.7-(225/2×√3/2)

=117.7-225×1.73/4

=81.6/4=20.4cm^2

area of major sector =(πr^2)-20.4cm^2

=706.5-20.4

=686.1cm^2