Question

6. A constant retarding force of 50N is applied on an object of mass
20kg moving initially with a velocity of 15m/s. How long does the
obiect take to stop? What distance would it cover during the time?

Answer 1

Answer:6s

Explanation:“good speed of 15m/s”???

Retardation (a) = F/m

= 50/20

= 2.5 m/s^2

Now, use v = u + at

0 = 15 + (-2.5)t

t = 15/2.5

t = 6 seconds

It takes 6s for body to stop.