6. A constant retarding force of 50N is applied on an object of mass
20kg moving initially with a velocity of 15m/s. How long does the
obiect take to stop? What distance would it cover during the time?
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Answer:6s
Explanation:“good speed of 15m/s”???
Retardation (a) = F/m
= 50/20
= 2.5 m/s^2
Now, use v = u + at
0 = 15 + (-2.5)t
t = 15/2.5
t = 6 seconds
It takes 6s for body to stop.
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